 | | | sort() | sort() 2004-03-08 - By Gregg Wygonik
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i'll assume your "list of usernames in a variable" is a delimited
list... so if you want to sort the contents of the string, overwriting
the unordered list, you could do something like this:
var a = "g|a|c|b|d|f|e|o|q|p|v|x|z|y";
a = a.split("|").sort().toString().split(",").join("|");
trace(a);
or - if you just want to output the values sorted, and leave the
original variable un-changed:
var a = "g|a|b|c|d|e|f|o|p|q|v|x|z|y";
trace(a.split("|").sort().toString().split(",").join("\n"));
hth
g.
-- --Original Message-- --
From: Simon Lord [mailto:slord@(protected)]
I now have a list of usernames in a variable that gets dumped to a
field. How can I sort the names in the variable so that when they get
dumped to the field they are sorted ascending from a to z?
Sincerely,
Simon
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