Copying an Array 2004-03-17 - By Merrill, Jason
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Easy enough to test:
myArray1 = []
myArray1 = [1,2,3,4,5]
myArray2 = myArray1
myArray1.pop();
trace(myArray1)
trace(myArray2)
This shows that myArray2 is a reference to myArray1, not a duplicate of
myArray1 since the 5 is missing from both. Change one, and you change the
other. i.e. even works the other way around:
myArray2.pop();
trace(myArray1)
trace(myArray2)
Only way I know how to make a "clone" copy of the entire array that could be
different from the original, would be by looping through and grabbing values,
and inserting them into the new array you create. Someone else might know. I
remember this came up before on one of the chattyfig lists.
Jason Merrill
ICF Consulting Government e-Learning Solutions
icfconsulting.com
:::>-- --Original Message-- --
:::>From: Brook Davies [mailto:blists@(protected)]
:::>Sent: Wednesday, March 17, 2004 4:13 PM
:::>To: flashnewbie@(protected)
:::>Subject: [Flashnewbie] Copying an Array
:::>
:::>
:::>I am wondering what is the best way to make a duplicate
:::>copy of an array or
:::>a position in an array. The array contains nested arrays
:::>and structures. If
:::>I was to say:
:::>
:::>myDuplicateArray = myArray[4]
:::>
:::>Would myDuplicateArray be a reference to the original data?
:::>I need a
:::>duplicate. What if myArray[4] contains a nested array and
:::>structures? Would
:::>it be duplicated or referenced?
:::>
:::>Brook
:::>
:::>
:::>
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